Arthur ran around a circular field for 3 times. If he ran a total distance of 726 m, what is the diameter of the field?
A. 77
B. 67
C. 57
D. 42
A. 77
B. 67
C. 57
D. 42
The distance is 726 and Arthur ran 3 times, so:
726:3
242
Now we search for the diameter.
[tex]2 \times \frac{22}{7} \times 242[/tex]
[tex] \frac{44}{7} \times 242[/tex]
We flip the 44/7 over.
[tex] \frac{7}{44} \times 242[/tex]
[tex]1964 \div 44[/tex]
or you can use:
[tex] \frac{1964}{44} [/tex]
= 38.5
38.5 x 2
77m (A)
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